Unit 12: Magnetic Fields and Electromagnetism
This unit covers the behavior of magnetic fields and their relationship with electric currents, charges in motion, and changing electric fields. Students will study how magnetic forces act on moving charges and current-carrying wires, apply the Biot–Savart Law and Ampère’s Law to calculate magnetic fields, and analyze the interplay between electricity and magnetism in Faraday’s Law of Induction. Understanding magnetic flux, inductance, and electromagnetic energy storage is essential for solving complex problems involving generators, transformers, and AC/DC circuit components. This unit builds on earlier topics by integrating vector calculus and symmetry principles to describe the unified nature of electromagnetic phenomena.
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Velocity Selector (Crossed \( \vec{E} \) and \( \vec{B} \) Fields)
- In crossed-field devices, a uniform electric field \( \vec{E} \) and magnetic field \( \vec{B} \) are arranged perpendicular to each other and to the incoming beam. A charged particle experiences electric force \( q\vec{E} \) and magnetic force \( q\,\vec{v}\times\vec{B} \) in opposite directions; only particles with speed \( v = \frac{E}{B} \) feel balanced forces and pass straight. Others are deflected up or down, so the apparatus “selects” a narrow speed band.
- This principle appears in mass spectrometers and e/m determinations, where the selector ensures a uniform entry speed before subsequent bending in a known magnetic field. An immediate check on set-up is units: \( E/B \) has units \( (\text{N/C})/(\text{T}) = \text{m/s} \), confirming it represents a speed. When solving, track the sign of \( q \) to determine the actual deflection direction.
Forces on Collections of Charge (Beams and Plasmas)
- For a narrow, monoenergetic beam, you can analyze a representative charge to determine the entire beam’s path because all particles share the same \( q/m \) and speed. In practice, small spreads in \( v \) cause slight radius differences \( r=\frac{mv}{|q|B} \), widening the beam downstream. Collisions or non-uniform fields can further broaden distributions, which is why focusing elements (magnetic lenses) are often used.
- In plasmas where both signs of charge are present, magnetic forces bend ions and electrons in opposite senses due to the sign of \( q \). Their very different masses also produce vastly different gyroradii and cyclotron frequencies, separating species. Understanding these scalings is crucial in fusion confinement and in space physics, where natural \( \vec{B} \) fields guide particle motion.
Practice Problems
Problem 1: RL Circuit Charging
A 12.0 V battery is connected in series with a 4.0 Ω resistor and a 2.0 H inductor. Determine the current in the circuit after 1.5 s.
Use \( I(t) = I_{\text{max}} \left(1 - e^{-t/\tau} \right) \) where \( \tau = \frac{L}{R} \).
Solution:
- Step 1: Calculate the time constant: \( \tau = \frac{L}{R} = \frac{2.0}{4.0} = 0.50 \ \text{s} \).
- Step 2: Determine \( I_{\text{max}} = \frac{V}{R} = \frac{12.0}{4.0} = 3.0 \ \text{A} \).
- Step 3: Substitute into the charging equation: \( I(1.5) = 3.0 \left(1 - e^{-1.5 / 0.50} \right) \).
- Step 4: Simplify: \( e^{-3} \approx 0.0498 \), so \( I(1.5) \approx 3.0 \times (1 - 0.0498) \approx 2.85 \ \text{A} \).
- Final Answer: \( I \approx 2.85 \ \text{A} \) after 1.5 s.
Problem 2: Magnetic Field from a Long Straight Wire
A long straight wire carries a current of 8.0 A. Calculate the magnetic field strength at a distance of 0.020 m from the wire.
Use \( B = \frac{\mu_0 I}{2\pi r} \) and \( \mu_0 = 4\pi \times 10^{-7} \ \text{T·m/A} \).
Solution:
- Step 1: Write the formula: \( B = \frac{\mu_0 I}{2\pi r} \).
- Step 2: Substitute values: \( B = \frac{(4\pi \times 10^{-7})(8.0)}{2\pi (0.020)} \).
- Step 3: Cancel \( \pi \) and simplify: \( B = \frac{(4 \times 10^{-7})(8.0)}{0.040} \).
- Step 4: \( B = \frac{3.2 \times 10^{-6}}{0.040} = 8.0 \times 10^{-5} \ \text{T} \).
- Final Answer: \( B = 8.0 \times 10^{-5} \ \text{T} \) (80 µT).